Find the least no which when divided
WebJan 17, 2024 · First, if a number is being divided by 10, then the remainder is just the last digit of that number. Similarly, if a number is being divided by 9, add each of the digits to each other until you are left with one number (e.g., 1164 becomes 12 which in turn becomes 3), which is the remainder. Webtomb 36 views, 0 likes, 0 loves, 2 comments, 0 shares, Facebook Watch Videos from St. Paul Lutheran Church: Scripture from NRSV Bible. Liturgy reproduced pursuant Augsburg Fortress #27464. Music...
Find the least no which when divided
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WebJun 13, 2024 · 2884 is the least number which when divided by 16, 18 and 20 leaves a remainder 4 in each case but exactly divisible by 7. Answer. Advertisement midhun9918 Hope it helps you...... First of all we have to take the L.C.M. of 16, 18 and 20 Prime factorization of 16 = 2*2*2*2 Prime factorization of 18 = 2*3*3 Prime factorization = 20 = … WebThe least number, which when divided by 48, 60, 72, 108 and 140 leaves 38, 50, 62, 98 and 130 as remainders respectively is. 11115; ... If each one likes at least one of these two games, then find the ratio between the number of people who like only cricket and the number of people who like only tennis. Q8. A certain sum of money is distributed ...
WebApr 5, 2024 · First of all we have to find the least number which on division with the 3 divisors gives the corresponding remainders so the least number is implying that we should take L.C.M of the three divisors and then we have subtracted from 10 to compensate the three different remainders. Latest Vedantu courses for you Grade 9 CBSE SCHOOL … WebApr 5, 2024 · By substituting the value of n in above equation, we get: Required number = (60 x 5) + 1 = 301 301 is divisible by 7. Therefore 301 is the least number which leaves remainder as 1 when divided by 2, 3, 4, 5, 6 and leaves no remainder when divided by 7. Option (b) is correct.
WebWe have to determine the least number which when divided by 2, 3, 4, 5 and 6 leaves 1 as a remainder and no remainder when divided by 7 Solution Let us determine the L C M of the numbers 2, 3, 4, 5 and 6 The value of L C M ( 2, 3, 4, 5, 6) obtained will be the smallest number that is exactly divisible by 2, 3, 4, 5 and 6 WebFind the smallest number which when divided by 28 and 32, respectively, leaves a remainder, 8 and 12 respectively. Solution Step 1: Find the LCM Given, 28 - 8 = 20 and 32 - ` 12 = 20 are divisible by the required numbers. Therefore, the required number will be 20 less than the LCM of 28 and 32 Prime factors of 28 are 28 = 2 × 2 × 7
WebTherefore, 3647 is the smallest number that when divided by 35, 56 and 91 leaves remainder of 7 in each case. ... Find the least number that is divisible by all the numbers between 1 and 10 (both inclusive). In a school there are two sections – section A and section B of Class VI. ...
WebApr 3, 2024 · The least possible number which when divided by 11, 12 and 13 leaves the remainder 7, 8 and 9 Concept used: Basic concept of number system and LCM In this type of question when a, b and c divided and leaves remainder d, e and f If the difference of terms is same Let (a - d) = (b - e) = (c - f) = K ∴ Required number is LCM of (a, b, c) -K grimmhof youtube neuesteWebMarius Moragues (@imperfectframe) on Instagram: "HAVE YOU HEARD ABOUT THE BADUY TRIBE? This tribe lives in several small villages at the foothill..." fifth wheel ohioWebApr 5, 2024 · From the above solution, the least number which on division by 35 leaves a remainder 25 and on division by 45 leaves the remainder 35 and on division by 55 leaves … grimmhof youtube neueste 225